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529x^2-1=0
a = 529; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·529·(-1)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-46}{2*529}=\frac{-46}{1058} =-1/23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+46}{2*529}=\frac{46}{1058} =1/23 $
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